Đề bài - câu 5 trang 33 sgk hóa 12 nâng cao

\[\eqalign{& C{H_2}OH - {\left[ {CHOH} \right]_3} - C - C{H_2}OH \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} C{H_2}OH - {\left[ {CHOH} \right]_4} - CHO \cr& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;\;\;\;\;\;\left\| {} \right. \cr& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;\;\;\;\;O \cr} \]

Đề bài

Viết phương trình của phản ứng sau [nếu có]:

a, Glucozơ tác dụng với nước brom

b,

Fructozơ \[+{H_2}\buildrel {Ni,t^\circ } \over
\longrightarrow \]

c,

Fructozơ +\[\left[ {Ag{{\left[ {N{H_3}} \right]}_2}} \right]OH\]\[\buildrel {} \over
\longrightarrow \]

d,

Glucozơ +\[\left[ {Ag{{\left[ {N{H_3}} \right]}_2}} \right]OH\]\[\buildrel {} \over
\longrightarrow \]

Lời giải chi tiết

a]

\[C{H_2}OH{\left[ {CHOH} \right]_4}CHO + B{r_2} + {H_2}O \to C{H_2}OH{\left[ {CHOH} \right]_4}COOH + 2HBr\]

b,

\[\eqalign{
& C{H_2}OH - {\left[ {CHOH} \right]_3} - C - C{H_2}OH + {H_2}\buildrel {Ni,t^\circ } \over
\longrightarrow C{H_2}OH - {\left[ {CHOH} \right]_4} - C{H_2}OH \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\left\| {} \right. \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;O \cr} \]

c,

\[\eqalign{
& C{H_2}OH - {\left[ {CHOH} \right]_3} - C - C{H_2}OH \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} C{H_2}OH - {\left[ {CHOH} \right]_4} - CHO \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;\;\;\;\;\;\left\| {} \right. \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;\;\;\;\;O \cr} \]

\[\eqalign{
& C{H_2}OH - {\left[ {CHOH} \right]_4} - CHO + 2\left[ {Ag{{\left[ {N{H_3}} \right]}_2}} \right]OH\buildrel {t^\circ } \over
\longrightarrow C{H_2}OH{\left[ {CHOH} \right]_4}COON{H_4} + 2Ag \downarrow + 3N{H_3} + {H_2}O. \cr
& \cr} \]

d,

\[\eqalign{
& C{H_2}OH - {\left[ {CHOH} \right]_4} - CHO + 2\left[ {Ag{{\left[ {N{H_3}} \right]}_2}} \right]OH\buildrel {t^\circ } \over
\longrightarrow C{H_2}OH{\left[ {CHOH} \right]_4}COON{H_4} + 2Ag \downarrow + 3N{H_3} + {H_2}O. \cr
& \cr} \]

loigiaihay.com

Video liên quan

Chủ Đề