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Math Expert
Joined: 02 Sep 2009
Posts: 87762
How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8,
[#permalink]
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How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8, 9 if no digit can be used more than once in a number ?
A. 120
B. 240
C. 360
D. 720
E. 1080
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Joined: 03 Oct 2013
Affiliations: CrackVerbal
Posts: 4988
Location: India
Re: How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8, [#permalink]
Basically the question is asking how many 5 digit numbers can be formed without repetition.
If we do by the box method, then the 1st place can be filled in 6 ways, second in 5, 3rd in 4 4th in 3 and the last in 2 ways.
Total number of ways = 6 * 5 * 4 * 3 * 2 = 720
In terms of permutations, we need to arrange 5 digit out of 6 = 6P5 = 6! / [6 - 5]! = 720 ways
In terms of combinations, first choose 5 numbers out of 6 in 6C5 ways and then arrange these 5 digits in 5! ways.
Total arrangements = 6C5 * 5! = 6 * 5! = 720
Option D
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How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8, [#permalink]
Bunuel wrote:
How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8, 9 if no digit can be used more than once in a number ?
A. 120
B. 240
C. 360
D. 720
E. 1080
We have 5 empty places like this
- - - - -
We have 6 digits to use and the digit can NOT be repeated
Method-1
So we can fill the first place in 6 ways
6 - - - -
So we can fill the Second place in 5 ways [can not use the used digit at first place]
6 * 5 - - -
So we can fill the Third place in 4 ways [can not use the used digits at previous places]
6 * 5 * 4 - -
So we can fill the Forth place in 4 ways [can not use the used digits at previous places]
6 * 5 * 4 * 3 -
So we can fill the Fifth place in 4 ways [can not use the used digits at previous places]
6 * 5 * 4 * 3 * 2
So total numbers =
720
ANswer: Option D
Method-2
Step-1: Select 5 out of 6 digits that need to be used to make a five digit number in
\[^6C_5\]
ways
Step-2: Arrange those selected
digits at 5 places in
5!
ways
Total Such numbers =
\[^6C_5*5! = 720\]
ANswer: Option D
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Re: How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8, [#permalink]
Total numbers: 6 [2, 3, 5, 6, 8, 9]
Condition: Repetition not allowed
Five-digit number: _, _, _, _, _
For first place from left, we have the choice of 6 numbers
For second place from left, we have the choice of 5 numbers
For third place from left, we have the choice of 4 numbers
For fourth place from left, we have the choice of 3 numbers
For fifth place from left, we have the choice of 2 numbers
=> 6 * 5 * 4 * 3 * 2 = 720
Answer D
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Re: How many 5-digit numbers can be formed from the digits 2, 3, 5, 6, 8, [#permalink]
01 Mar 2021, 08:02
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